Ratio-Proportion-Variation Notes for Competitive Exams Preparation
Ratio:
Ratio is the relation which one quantity bears to another of the same kind, the comparison being made by considering what multiple, part or parts, one quantity is of the other. The ration of two quantities "a" and "b" is represented as a : b and read as "a is to b". "a" is called antecedent, "b" is the consequent. Since the ratio expresses the number of times one quantity contains the other, its's an abstract quantity.
A ratio a : b can also be expressed as a/b. So if two items are in the ratio 2 : 3, we can say that their ratio is 2/3. If two terms are in the ratio 2, it means that they are in the ratio of 2/1, ie., 2 :1.
" A ratio is said to be a ratio of greater inequality of less inequality or of equality according as antecedent is greater than, less than or equal to consequent". From this we find that a ratio of greater inequality is diminished and ratio of less inequality is increased by adding same quantity to both terms.
ie., in a : b
If a<b then (a+x) : (b+x)> a: b and a>b then (a+x):(b+x) < a:b
if a/b=c/d=e/f ...., then each of these ratio is equal to a+c+e+..../b+d+f+...
Proportion:
When two ratios are equal the four quantities involved in the two ration are said to be proportional
ie., If a/b= c/d, then a, b, c and d are proportional. This is represented as a:b :: c:d and si read as "a is to b (is) as c is to d".
When a, b, c and d are in proportion, then the items a and d are called the EXTREMES and the items b and c are called the MEANS. We also have the relationship.
Product of the MEANS = Product of the EXTREMES ie., bc= ad
If a:b = c:d then
b:a = d:c----(1)
a: c= b:d
a+b: b= c+d:d....(2) obtained by adding 1 to both sides of the given relationship
a-b:b=c-d:d.....(3) obtained by subtracting 1 from both sides of the given relationship
a+b:a-b=c+d:c-d .....(4) obtained by dividing relationship (2) above by (3).
Relationship
(1) above is called INVERTENDO
(2) is called COMPONENDO
(3) is called DIVIDENDO and
(4) is called COMPONENDO- DIVIDENDO.
The last relationship, ie., COMPONENDO-DIVIDENDO is very helpful in simplifying problems.
Whenever we know a/b=c/d, then we can write (a+b)/(a-b)=(c+d)/(c-d) by this rule. The converse of this is also true whenever we know that (a+b)/(a-b)= (c+d)/(c-d), then we can conclude that a/b=c/d.
If three quantities a, b and c are such that a:b :: b:c , then we say that they are in CONTINUED PROPORTION. We also get b square= ac
Variation:
Two quantities A and B may be such that as one quantities changes in value, the other quantity also changes in value depending on the change in the value of the first quantity.
Direct Variation:
One quantity A is said to vary directly as another quantity B if the two quantities depend upon each other in such a manner that if B is increased in a certain ration, A is increased in the same ratio and if B is decreased, A is decreased in the same ratio.
This is denoted as A alpha B then A= kB, where k is a constant. It is called a constant of proportionality.
Inverse Variation:
A quantity A is said to vary inversely as another quantity B if the two quantities depend upon each other in such a manner that if B is increased in a certain ratio, A is decreased in the same ratio and if B is decreased then A is increased in the same ratio. It is the same as saying that A varies directly with 1/B. It is denoted as if A alpha 1/B i.e., A=k/B, where k is a constant of proportionality.
Joint Variation:
If there are three quantities A, B, and C such that A varies with B when C is constant and varies with C when B is constant, then A is said to vary jointly with B and C when both B and C are varying.
then A alpha BC or A=kBC, where k is the constant of proportionality.
Worked Out Examples:

Sol:- x/y= 9/11
Let x= 9k, y= 11k
9k+5/11 k+5=5/6
54k+30=55 k+25
k= 5
x=9(5)=45
y=11(5)= 55
2) The volume of cylinder varies jointly as its height and the area of its base. When the area of the base is 300 square feet and the height is 6 feet the volume is 600 cu.ft. what is the area of the base of a cylinder whose volume is 360 cu.ft. and height is 12 ft.
Sol:- Let v be the volume, a be the area of base, h be the height.
V=m a h, where m is the constant.
Therefore, 600=m(300)(6)
1/3=m
therefore V=1/3(a)(h)
Now, 360 = 1/3(a)(12)
a= 90 sq.ft.
Important Links:
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